Question 987989: The longest side of an obtuse triangle measures 20 cm. The two shorter sides measure x cm and 3x cm. Rounded to the nearest tenth, what is the greatest possible value of x?

Question

Mathematics

Gilbert Ryan

5 March, 02:48

Question 987989: The longest side of an obtuse triangle measures 20 cm. The two shorter sides measure x cm and 3x cm. Rounded to the nearest tenth, what is the greatest possible value of x?

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Answers (1)

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Carleigh Curtis · Answer 1

Given that the longest side is 20 cm, 3x < 20 and x <20/3

Other inequality that has to be checked is that the sum of two any sides has to be greater than the other.

Then 3x + x > 20

4x > 20

x > 5.

So the value of x is in the range (5, 20/3)