1. Find the zeros of f (x) = x2 - 9

2. Find the zeros of the function h (x) = 3x2 + 13x + 4

3. Find the zeros of the function g (x) = x2 - 6x - 16

4. Find the zeros of f (x) = x2 + 4x - 5

So for the first one it is (x-3) (x+3) this is because it is a difference of squares so you square root the 9 and the minus you do both + and - in order to keep up the - 9

The zeros are:x=3 and x=-3 (this is because you change the sign in the bracket

the others should be pretty simple to do for number 2 its a complex

the third is a simple trinomial

and fourth is simple trinomial as well