Solve the system below

y=x^2-2x-6

y=4x+10

A. (-2,2)

B. (8,42)

C. (-2,2), (8,42)

D. No real solution

Solve the system below

y=x^2 - 4

y = - 4

A. (0,-4)

B. (-4,0)

C. (0,-4), (-4,0)

D. No real solution

Question

Mathematics

Taylor Hurst

6 May, 22:38

Solve the system below

y=x^2-2x-6

y=4x+10

A. (-2,2)

B. (8,42)

C. (-2,2), (8,42)

D. No real solution

Solve the system below

y=x^2 - 4

y = - 4

A. (0,-4)

B. (-4,0)

C. (0,-4), (-4,0)

D. No real solution

+3

Answers (1)

Know the Answer?

Amaris Farley · Answer 1

For the system y=x^2-2x-6 & y=4x+10 the answer is A. (-2,2)

y=-2^2-2 (-2) - 6

y=4+4-6

y=8-6

y=2

y=4x+10

y=4 (-2) + 10

y=-8+10

y=2

For the system y=x^2-4 & y=-4 the answer is

A. (0,-4)

y=0^2-4

y=-&

For the system

Solve the system belowy=x^2-2x-6y=4x+10A. (-2,2)B. (8,42)C. (-2,2), (8,42)D. No real solutionSolve the system belowy=x^2 - 4y = - 4A. (0,-4)B. (-4,0)C. (0,-4), (-4,0)D. No real solution

Solve the system below

y=x^2-2x-6

y=4x+10

A. (-2,2)

B. (8,42)

C. (-2,2), (8,42)

D. No real solution

Solve the system below

y=x^2 - 4

y = - 4

A. (0,-4)

B. (-4,0)

C. (0,-4), (-4,0)

D. No real solution