Find the coordinates for the vertex of the graph of the function y = 3x^2 - 12x + 12

First, you have to put the graph in vertex form by factoring. there is a GCF of 3, so take it out of the equation.

3 (x²-4x+4).

now do bottoms up method.

1 * 4 = 4, and - 4 is the middle number.

-2 and - 2 multiply to 4 and add up to - 4.

factor: 3 (x-2) (x-2). vertex form 3 (x-2) ²

vetex coordinates: (2,0)