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26 November, 11:16

Find the range of the function f (x) = x2-6x.

If the domain is (-7,-2,1)

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  1. 26 November, 14:29
    0
    Hello:

    1) x²-6x = - 2

    x²-6x+2=0

    x²-2 (3) x+9-9+2 = 0

    (x-3) ² - 7 = 0

    (x-3) ² = (√7) ²

    x-3 = √7 or x-3 = - √2

    x=3 + √2 or x = 3 - √2

    2) x²-6x = - 7

    x²-6x+7=0

    x²-2 (3) x+9-9+7 = 0

    (x-3) ² - 7 = 0

    (x-3) ² = (√7) ²

    x-3 = √7 or x-3 = - √7

    x=3+√7 or x = 3-√7

    3)

    x²-6x = 1

    x²-6x-1=0

    x²-2 (3) x+9-9-1 = 0

    (x-3) ² - 10 = 0

    (x-3) ² = (√10) ²

    x-3 = √10 or x-3 = - √10

    x=3 + √10 or x = 3 - √10

    the range is : {3+√2,3-√2,3+√7,3-√7,3 + √10, 3 - √10 }
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