Simplify the radical expression square root of 490y^5w^6

Rewrite this as √ (49·10·y⁴·y· (w³) ²).

Any squared term under the radical sign can be taken outside, in the form of its square root:

√a² = a; √ (a²b) = a√b; etc.

Note that 49, y⁴, and (w³) ² are all squares; their square roots are 7, y², and w³. Take all these outside, leaving the other (irreducible) terms inside:

So the final answer is 7y²w³√ (10y)