Ask Question
22 February, 04:06

2 sin 2θ - 3 sin θ = 0

+1
Answers (2)
  1. 22 February, 05:13
    0
    Sin2θ = 2sinθcosθ

    2 sin 2θ - 3 sin θ = 0

    2 (2sinθcosθ) - 3 sin θ = 0

    4sinθcosθ - 3sin θ = 0

    sinθ (4cosθ - 3) = 0

    sinθ = 0, 4cosθ - 3 = 0 cosθ = 3/4

    θ = sin⁻¹ (0) θ = cos⁻¹ (0.75)

    θ = 0, 180, 360 degrees, θ ≈ 41.41°, 360 - 41.41 = 318.59°

    θ = 0°, 180°, 360°, ≈ 41.41°, ≈ 318.59°
  2. 22 February, 06:47
    0
    (-1/4)

    ...
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “2 sin 2θ - 3 sin θ = 0 ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers