What is the directrix of the parabola defined by 1/4 (y 3) = (x-2) ^2?

For

(x-h) ^2=4p (y-k)

vertex = (h, k)

p=vertical distance from vertex to directix

when p is negative, the directix is above the vertex

when p is positive, the directix is below the vertex

(x-2) ^2=1/4 (y+3)

(x-2) ^2=4 (1/16) (y+3)

p=1/16

it's positive so we know directix is below vertex

vertex is (2,-3)

go 1/16 down

-3-1/16=-48/16-1/16=-49/16

directix is y=-49/16 aka y=-3.0625