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14 October, 05:22

What are the first four terms in tn=3n+2

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  1. 14 October, 09:20
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    For this question we are looking at arithmetic sequences. A sequence is any set of numbers in a particular order. An arithmetic sequence is a specific type of sequence where the difference between 2 consecutive terms is constant. The difference is called the common difference. In your problem ...

    t_n = 3n + 2

    we need to find the common difference, then we can find the 1st four terms. Find the 1st term by replacing n with 1.

    t_1 = 3 (1) + 2

    t_1 = 3 + 2 = 5

    Find the second term by replacing n with 2

    t_2 = 3 (2) + 2 = 8

    and so on

    t_3 = 3 (3) + 2 = 11

    t_4 = 3 (4) + 2 = 14

    The 1st 4 numbers in the sequence are 5,8,11, and 14.

    You can see the common difference is d=3. You could plug any number into the equation to find that number in the sequence. For example, the 100th number in the sequence would be

    t_100 = 3 (100) + 2 = 302
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