If (a, b) is the center and r is the radius of the circle defined by the parametric equations

what is the value of a+b+r?

x = 10cos 3t, y = 10sin 3t 0≤t≤ 2pi

This is a bonus problem it is extremely difficult

Those particular parametric equations generate a circle with its

center at the origin (0, 0). So ' a ' and ' b ' are both zero.

The (radius of the circle) ² is (10² + 10²) = 200

Radius = √200

So (a + b + r) = √200. (about 14.1421)

The significance of the ' 3t ' in the argument of the 'x' and 'y' is just that as

't' goes from zero to 2π, the parametric equations draw the circle 3 times.