If the hypotenuse of a right triangle is 2 sqrt 3 units long and one legs is sqrt 3 units long, how long is the other leg?

a. 3

b. 2 sqrt 3

c. sqrt 3

Theorem of Pythagoras: a²+b²=c², where a, b is legs and c is hypotenuse.

We've got one leg known, let it be a=sqrt 3,

and the hypotenuse - c=2sqrt3

Putting these into the theorem, we get an equation: (sqrt3) ²+b² = (2sqrt3) ². Solving it, we get:

3+b²=4*3

3+b²=12

b²=9

This equation has two possible roots: b=3 and b=-3. Since this is a triangle, there can't be a side with a negative value = > b=3.

The answer is a. 3