Ask Question
6 October, 17:34

John Sells Hamburgers For $3 Each and cheeseburgers for $3.50 each. One afternoon, he sells a total of 24 burgers for $79. How Many hamburgers did he sell?

+1
Answers (1)
  1. 6 October, 18:39
    0
    Let the hamburgers be x and cheese burgers be y.

    x + y = 24

    3x + 3.5 y = 79

    x = 24 - y.

    Substituting the value of x,

    3 (24 - y) + 3.5 y = 79

    72 - 3y + 3.5 y = 79

    72 + 0.5 y = 79

    0.5y = 79 - 72 = 7

    1/2 y = 7

    thus, y = 7 * 2 = 14

    Substituting the value for x,

    x + y = 24

    x + 14 = 24

    x = 24-14 = 10

    Thus, x = 10.

    Thus, she sold 10 hamburgers and 14 cheeseburgers
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “John Sells Hamburgers For $3 Each and cheeseburgers for $3.50 each. One afternoon, he sells a total of 24 burgers for $79. How Many ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers