A rectangle has an area of 30 sq. meters, and a perimeter of 34 meters. What is the dimension?

Area = l * w

30 = l * w

Perimeter = 2l + 2w

34 = 2l + 2w

Let's get the width from the Area and substitute it in the perimeter

w = 30/l

34 = 2l + 2w

34 = 2l + 2 (30/l)

34 = 2l + (60/l)

34 = (2l^2 + 60) / l

34l = 2l^2 + 60

17l = l^2 + 30

0 = l^2 - 17l + 30

(l-15) (l-2)

l-15 = 0

l=15

l-2 = 0

l = 2

Length can either be 15 or 2

So the dimensions are 15 and 2.