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25 January, 16:02

What values of x and y satisfy - 133x-2y=7 and 3x+25y=5 simultaneously?

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  1. 25 January, 17:20
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    1) - 133x - 2y = 7

    2) 3x + 25 y = 5

    Multiply 1) by 25 and 2) by 2, then

    1a) - 3325x - 50y = 175

    2a) 6x + 50y = 10

    Add the 1a) and 2a)

    3) - 3319x = 185

    x = - 185 / 3319 = - 0.056

    from 1) y = (-133 (x) - 7) / (2) = [-133 (-185/3319) - 7]/2 = 0.207
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