What is least perimeter of a rectangle with an area 32 square feet

If you have a rectangle with an area of 32 square feet, it means that the sides are

A=L x W, 32 = 8*4, where

L=8, W=4

other options are

L=16, W=2 and the last one is

L=32, W=1

You need to find the least perimeter, and you know that the perimeter is P = 2 (L+W)

Perimeter (1) = 2 (8+4) = 2*12=24

Perimeter (2) = 2 (16+2) = 2*18=36

Perimeter (3) = 2 (32+1) = 2*33=66

The least perimeter is 24, with the sides L=8 and W=4