Find a polynomial of degree 3 with a real coefficient that satisfies the given condition. Zeros: - 2, 1, 0; f (2) = 32

Its factors would be

(x+2) * (x-1) * (x+0)

x^2 + x - 2

x^3 + 0 + x^2 + 0 - 2x + 0

Equation: x^3 + x^2 - 2x

f (2) = 8 + 4 - 4

2x^3 + 2x^2 - 4x + 0

f (2) = 16 + 8 - 8

3x^3 + 3x^2 - 6x + 0

f (2) = 24 + 12 - 12

4x^3 + 4x^2 - 8x + 0

f (2) = 32 + 16 - 16

So, the equation is:

4x^3 + 4x^2 - 8x = 0