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25 March, 13:12

How much greater is the surface area of a basketball with a radius of 4.7244 inches than the surface area of a tennis ball with a radius of 1.2598 inches? Round to the nearest hundredth

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  1. 25 March, 15:45
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    The surface area of a sphere is the product when 4 is multiplied to π and square of radius. For the basketball,

    SA = 4π x (4.7244 in) ² = 280.48 in²

    For the tennis ball,

    SA = 4π x (1.2598 in) ² = 19.944 in²

    To answer the question, determine the difference of their surface area. That is,

    280.48 in² - 19.944 in² = 260.90 in²
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