The length of a rectangle is 4 more than twice the width the perimeter is 28 what is the length

Perimiter=2 (legnt+width)

or

p=2 (l+w)

l=4+2w

p=28

28=2 (l+w)

subsitte 4+2w for l

28=2 (4+2w+w)

28=2 (4+3w)

28=8+6w

subtract 8 from both sdies

20=6w

divide by 6

20/6=w

aprox

3 2/3=3.666666

so 3 2/3=width

Perimeter = length + length + width + width

if the perimeter is 28, then:

28 = length + length + width + width

if you know that the length is 4 more than twice the width, then:

length = 4 + 2 x width

(using L as length, and w as width then: L = 4 + 2w)

if you substitute that back into the equation

28 = L + L + w + w

you should get

28 = 4 + 2w + 4 + 2w + w + w

combine the 4's and the ws

28 = 8 + 6w

subtract both sides by 8

22 = 6w

divide both sides by 6

w = 3 2/3