What are two consecutive odd integers whose product is 99.

Consecutive odd integers are 2 apart

they 2 numbers are

n and n+2

their product is 99

n times n+2=99

n (n+2) = 99

n²+2n=99

minus 99 both sides

n²+2n-99=0

what 2 numbres multiply to - 99 and add to get 2

if you can't do that

complete square

n²+2n+1-100=0

(n+1) ²-100=0

(n+1) ²=100

sqrt both sides

n+1=+/-10

n=-1+/-10

n=-11 or 9

if n=-11, then n+2=-9

if n=9 then n+2=11

the integers are - 11 and - 9 or 9 and 11