There are 4 red marbles, 3 blue marbles, and 3 yellow marbles in a bag. What is the probability of first drawing a blue marble and then drawing another blue marble without replacement?

Probability = no of outcomes / total outcomes

First draw = no of blue mables / total mables = 3 / (4 + 3 + 3) = 3/10

For the second draw, since there was no replacement of the first draw, the blue mables has reduced by one, and the total mables has reduced by one.

Second draw = no of remaining blue mables / total remaining mables = 2/9

Probability for both draws = 3/10 x 2/9 = 1/15