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28 January, 07:08

For what value of x will sin x = cos 19°, given 0°< x < 90°?

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  1. 28 January, 08:18
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    Sin x = cos 19°; 0° < x < 90°

    cos is the complementary of sine. This means that the value of x in sin x and the value of 19° in cos 19° adds up to 90°

    x + 19° = 90°

    x = 90° - 19°

    x = 71°

    sin 71° = cos 19°

    0.9455 = 0.9455

    The value of x is 71°
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