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There are 14 performers who will present their acts this weekend at a comedy club. One of the performers insists on being the last stand-up comic of the evening, and another performer wants to be the first. Determine how many different ways can the appearances be scheduled.

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  1. Today, 00:47
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    Given:

    14 performers

    first spot claimed; last spot claimed.

    14 - 1 - 1 = 12

    12 spots remaining for everybody else. Permutation.

    12! = 479,001,600
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