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4 January, 08:16

If a ball is thrown into the air with a velocity of 42 ft/s, its height (in feet) after t seconds is given by y = 42t - 16t2. Find the velocity when t = 1.

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  1. 4 January, 10:02
    0
    Velocity is found using the first derivitive, y'=42-32t

    evaluating this as t=1 gives the velocity after 1 second which is 10ft.
  2. 4 January, 10:45
    0
    I'm pretty sure its 10
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