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28 June, 22:47

Explain how you can find the lengths of the two legs of a 30 60 90 degree triangle in radical form if you are given the length of the hypotenuse

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  1. 28 June, 23:17
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    If you use the formula a/SinA = b/SinB or C and c depending on which side you are trying to find. Remember the leg across from the angle will have the same variable only the Angle's will be capital and the leg's will be lowercase
  2. 29 June, 00:58
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    I heard my geometry teacher recite this so often that

    I can still recite it from memory:

    "In a 30 - 60 right triangle, the side opposite the 30 is

    half of the hypotenuse, and the side opposite the 60 is

    half of the hypotenuse times the square root of 3."

    That was almost 60 years ago, but I believe it's still true.

    He was quite a memorable teacher.
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