Find f. (antiderivative). f ' (t) = 4 cos (t) + sec^2 (t), - π/2 < t < π/2, f (π/3) = 3

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Mathematics

Damien Copeland

20 January, 11:17

Find f. (antiderivative). f ' (t) = 4 cos (t) + sec^2 (t), - π/2 < t < π/2, f (π/3) = 3

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Mekhi Combs · Answer 1

The antiderivative of the function f ' (t) = 4 cos (t) + sec^2 (t) is determined by applying integral calculus. The antiderivative of 4 cos (t) is - 4 sin (t) while the antiderivative of sec^2 (t) is tan (t). The total term is - 4 sin (t) + tan (t). We try to replace pi/3 and the answer is 3.