X^2cos^2y-siny=0 derivate and find equation of tangent & normal

Given the equation: x^2cos^2y - sin y = 0

This equation can't be expressed explicitly with respect to y due to the presence of trigonometric functions. Thus, the equation will be differentiated implicitly with respect to x and y. Then, rearrange the equation to look like this:

y' = f (x); to solve for the equation of tangent and normal, equate f' (x) to zero.