Ask Question
1 June, 19:02

A cylinder and a cone start with the same radius and height. The radius of the cone is then tripled, and the height of the cone is cut in half. The radius of the cylinder stays the same, but the height of the cylinder is doubled. Which change produces a greater increase in volume (i. e., which figure's volume increases by a larger factor) ? Justify your answer. Write "pi" for ^ and "r^2" for r squared

+3
Answers (1)
  1. 1 June, 19:45
    0
    Cone:

    Original cone = (1/3) π (h) r^2

    Changed cone = (1/3) π (h/2) (3r) ^2

    = (1/2) (1/3) π (h) 9r^2

    = (9/2) * Original cone

    =4.5 * Original cone

    Cylinder:

    Original cylinder = π (h) r^2

    Changed cylinder = π (2h) r^2

    =2 * Original cylinder

    Therefore the cone is the greatest relative increase in volume.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A cylinder and a cone start with the same radius and height. The radius of the cone is then tripled, and the height of the cone is cut in ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers