What is the solution set of 6x^2 - 24 = 0?.

A.) {-2, 2}

B.) {-2}

C.) {2}

Question

Mathematics

Jazmin Benton

9 July, 10:32

What is the solution set of 6x^2 - 24 = 0?.

A.) {-2, 2}

B.) {-2}

C.) {2}

+5

Answers (2)

Know the Answer?

Kayla Medina · Answer 1

If xy=0 then assume taht x and/or y=0

remember differnce of 2 perfect squares

a^2-b^2 = (a-b) (a+b)

factor

6x^2-24=0

6 (x^2-4) = 0

6 (x^2-2^2) = 0

6 (x-2) (x+2) = 0

set to zero

x-2=0

x=2

x+2=0

x=-2

x=2 and - 2

A is answer

Sidney Donaldson · Answer 2

We are given with the expression 6x^2 - 24 = 0. We are asked in the problem for its solution set. The first step to take is to factor out 6 in the equation resulting to x^2 - 4 = 0. This is a special type of equation where after factoring the equation becomes (x-2) * (x+2) = 0. Hence the solution set is A. {-2,2}

What is the solution set of 6x^2 - 24 = 0?.A.) {-2, 2}B.) {-2}C.) {2}

What is the solution set of 6x^2 - 24 = 0?.

A.) {-2, 2}

B.) {-2}

C.) {2}