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11 March, 17:37

How many liters of a 20% solution of a chemical should be mixed with 15 liters of 50% solution to obtain a 30% mixture

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  1. 11 March, 18:45
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    20x + 50y = 30 (x + y) y = 15---put the system of linear equations into standard form:---20x + 50y = 30x + 30yy = 15---10x - 20y = 0y = 15---answer:x = 30 liters of 20%y = 15 liters of 50%---resulting solution: 45 liters of 30%
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