How to solve this equation 2 (f+3) + 4f=6+6f?

2f+6+4f=6+6f

6f+6-6=6-6+6f

6f=6f

This means f can equal any number which we call mathematically infinite solution or infinitely many solutions

Step 1: Simplify both sides of the equation.

2 (f+3) + 4f=6+6f

Simplify: (Show steps)

6f+6=6f+6

Step 2: Subtract 6f from both sides.

6f+6-6f=6f+6-6f

6=6

Step 3: Subtract 6 from both sides.

6-6=6-6

0=0

Answer:

All real numbers are solutions.