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30 January, 23:57

How to solve this equation 2 (f+3) + 4f=6+6f?

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Answers (2)
  1. 31 January, 00:56
    0
    2f+6+4f=6+6f

    6f+6-6=6-6+6f

    6f=6f

    This means f can equal any number which we call mathematically infinite solution or infinitely many solutions
  2. 31 January, 01:45
    0
    Step 1: Simplify both sides of the equation.

    2 (f+3) + 4f=6+6f

    Simplify: (Show steps)

    6f+6=6f+6

    Step 2: Subtract 6f from both sides.

    6f+6-6f=6f+6-6f

    6=6

    Step 3: Subtract 6 from both sides.

    6-6=6-6

    0=0

    Answer:

    All real numbers are solutions.
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