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23 June, 06:46

Solve the following equation on the interval [0,2 / pi)

Cot (3x) = / sqrt{3}

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  1. 23 June, 06:51
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    Cot (3x) = 3^ (1/2)

    cot (x) = cos (x) / sin (x)

    cot (3x) = cos (3x) / sin (3x)

    look at a unit circle chart

    find a value for cos that has sqrt (3) in it

    which one will reduce so that the cos/sin will equal sqrt (3) ?

    pi/6 radians

    now cot (3x) implies that x is one third this value

    pi/18 is the answer
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