Consider this system of equations:

2/3x+3/5y=12 (equation A)

5/2y-3x=6 (equation B)

The expression that gives the value of x is:

The solution for the system of equations is:

To find the value of x, we have to eliminate y by making y the subject of formula in any of the equations.

Multiply equation A by 5/3 t. o get,

5/3 (2/3x) + 5/3 (3/5y) = 5/3 (12)

10/9x + y = 20

y = 20 - 10/9x

substituting for y into equation b, we have:

5/2 (20 - 10/9x) - 3x = 6

50 - 25/9x - 3x = 6

52/9x = 44

52x = 396

The expression that gives the value of x is: 52x = 396

Hence, x = 396/52 = 99/13

y = 20 - 10/9 (99/13) = 20 - 110/13 = 150/13

The solution for the system of equations is: (99/13, 150/13)