Ask Question
27 June, 14:12

At 5:45 p. m., a jet is located 108 mi due east of a city. A second jet is located 214 mi due north of the city. To the nearest tenth of a mile, what is the distance between the two jets? Enter your answer as a decimal in the box.

+2
Answers (1)
  1. 27 June, 16:55
    0
    By connecting the distances traveled by the jet and the distance between them, we form a right triangle with hypotenuse equal to the unknown distance.

    Using the Pythagorean,

    h² = a² + b²

    Substituting,

    h² = (108 mi) ² + (214 mi) ²

    h = 239.71 miles

    Thus, the distance between them is approximately 239.71 miles.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “At 5:45 p. m., a jet is located 108 mi due east of a city. A second jet is located 214 mi due north of the city. To the nearest tenth of a ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers