Decide which of the following are solutions to this system of equations: y = 2x + 3 and y = x2 - 5

a. (4,11)

b. (1,-4)

c. (-3,-1)

d. (-2,-1)

Y = 2x + 3

y = x² - 5

2x + 3 = x² - 5

- 3 - 3

2x = x² - 8

- 2x - 2x

0 = x² - 2x - 8

x = - (-2) ± √ ((-2) ² - 4 (1) (-8))

2 (1)

x = 2 ± √ (4 + 32)

2

x = 2 ± √ (36)

2

x = 2 ± 6

2

x = 1 ± 3

x = 1 + 3 U x = 1 - 3

x = 4 x = - 2

y = 2x + 3

y = 2 (4) + 3

y = 8 + 3

y = 11

(x, y) = (4, 11)

y = 2x + 3

y = 2 (-2) + 3

y = - 4 + 3

y = - 1

(x, y) = (-2, - 1)

The two answers Is equal to A and D.