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1 May, 07:17

How many solutions are possible for a triangle with B=44, a=23 and b=12?

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  1. 1 May, 07:23
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    B = 44 degrees

    a = 23

    b = 12

    use law of sines to solve for angle A:

    b/sinB = a/sinA

    12/sin44 = 23/sinA

    12sinA = 23*sin44

    sinA = (23*sin44) / 12

    sinA = 1.3314

    since sinx is only defined for values between - 1 and 1 it is impossible to form a triangle with given the dimensions. hence no possible solutions
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