A parallelogram has an area of 42 cm2. What would the area be if the base was one-third as long and the height was twice as long?

The area of the original parallelogram is expressed as, A = b x h which is equal to 46 cm². The second parallelogram has dimensions equal to b/3 and 2h. Its area is,

A = (b/3) x (2h) = 2bh/3

which is equal to A = 2 (bh) / 3 = 2 (46 cm²) / 3 = 30.67 cm²

Thus, the area of the second parallelogram is approximately 30.67 cm².