The sum of three consecutive even integers is 30 more than the smallest integer

Let's call the smallest of the three even integers ' T ' (for 'tiny')

The second even number is T + 2.

The third even number is T + 4.

Add up the 3 even numbers: T + (T + 2) + (T + 4) = 3T + 6

This is 30 more than the smallest of the three.

3T + 6 = T + 30

Subtract T from each side: 2T + 6 = 30

Subtract 6 from each side: 2T = 24

Divide each side by 2 : T = 12

The three consecutive even integers are 12, 14, and 16.

Check: 12 + 14 + 16 = 42. By George, that's 30 more than 12!