Ask Question
16 July, 23:54

Sylvanite is a mineral that contains 28.0% gold by mass. Determine how much sylvanite would you need to dig up to obtain 81.0 g of gold.

+4
Answers (1)
  1. 17 July, 00:13
    0
    Since Sylvanite only contains 28% gold by mass, then to obtain 81.0 grams of gold, x amounts of sylvanite must be mined. To determine x, we divide 81 grams by 28%. This equation is shown below:

    0.28X = 81

    X = 81/0.28

    X = 289.29 grams

    Therefore, 289.29 grams of sylvanite must be dug up to obtain 81 grams of gold.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Sylvanite is a mineral that contains 28.0% gold by mass. Determine how much sylvanite would you need to dig up to obtain 81.0 g of gold. ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers