Which value of b will cause the quadratic equation x2 + bx + 5 = 0 to have two real number solutions?

-5

-3

3

4

Question

Mathematics

Jacey

7 April, 08:52

Which value of b will cause the quadratic equation x2 + bx + 5 = 0 to have two real number solutions?

-5

-3

3

4

+2

Answers (2)

Know the Answer?

Boss · Answer 1

What 2 numbers multiplty to get 5 and add to get b?

5*1=5

5+1=6

b=6 is the answer

b has to be 6'

the answer is not listed, but if that equation was x^2+bx-5=0, then b=4

answer is b=6

Gerardo Dillon · Answer 2

Which value of b will cause the quadratic equation x2 + bx + 5 = 0 to have two real number solutions?

-5

Which value of b will cause the quadratic equation x2 + bx + 5 = 0 to have two real number solutions?-5-334

Which value of b will cause the quadratic equation x2 + bx + 5 = 0 to have two real number solutions?

-5

-3

3

4