Ask Question
30 November, 08:58

Jean bought a bag of candy that contained red candies, green candies, and brown candies. Some candies are marked with a smile and others are not marked. The probabilities are displayed in the table below:

| Red |Green |Brown

Smile |0.100 |.300 |.10

No smile |0.200 |.150 |.15

If a random candy is chosen from this bag, what is the probability that the candy was red or had no smile?

+1
Answers (2)
  1. 30 November, 09:03
    0
    | Red |Green | Brown Total

    Smile |0.100 |.300 |.10 0.50

    No smile |0.200 |.150 |.15 0.50

    Total 0.30 0.45 0.25 1.00

    The probability of choosing red candy is 0.10

    The probability of choosing no smile candy is 0.50

    The probability of choosing red or no smile = 0.10 + 0.50 = 0.60

    I did not use 0.30 as the probability of red because it included the no smile candy. It should only be red candy that has a smile.
  2. 30 November, 12:06
    0
    The correct answer is:

    A: 0.60
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Jean bought a bag of candy that contained red candies, green candies, and brown candies. Some candies are marked with a smile and others ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers