Solve x^2 6x = 7 by completing the square. which is the solution set of the equation? a. {-7, 1} d. {1, 7}

X^2+6x=7

take 1/2 of 6 and square it (3^2=9)

add that to both sides

x^2+6x+9=7+9

x^2+6x+9=16

factor perfect square

(x+3) ^2=16

square root both sides

remembe to take the positive and negative square roots

x+3=+/-4

minus 3 from both side

x=+/-4-3

x=-7 or 1

A is answer