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26 January, 17:01

A boy has twice as many nickels as he has pennies, and he has 5 less dimes than nickels. If he has $4.46 in all, how many coins of each kind does he have?

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  1. 26 January, 20:56
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    N=2p

    n/2=p

    n-5=d

    10d+5n+1p=446

    subsitute n/2 for p

    subsitute n-5 for d

    10 (n-5) + 5n+n/2=446

    times 2 both sides

    20 (n-5) + 10n+n=892

    expand

    20n-100+10n+n=892

    31n-100=892

    add 100 both sides

    31n=992

    divide both sides by 31

    n=32

    subsitute back

    n/2=p

    32/2=16=p

    n-5=d

    32-5=d=27

    27 dimes

    16 pennies

    32 nickles
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