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17 October, 03:58

Suppose the definite integral, bottom value 2, top value 6 of g (x) dx=12 and the definite integral bottom value 5 top value 6 of g (x) dx = - 3, find the value of the definite integral bottom value 2 and top value 5 of 3g (x) dx

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  1. 17 October, 06:16
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    The definite integral would be equal to your value from 2 to 6 minus your value from 5 to 6.

    12 - (-3) = 15
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