Find the x-intercept (s) and the coordinates of the vertex for the parabola

=y+x^2-8x+12

The factors of the expression are:

y = (x - 2) (x - 6)

The x-intercepts are found by putting y = 0.

Therefore the x-intercepts are at (2, 0) and (6, 0).

The x value of the vertex is (2 + 6) / 2 = 4.

f (4) = 16 - 32 + 12 = - 4.

The coordinates of the vertex are (4, - 4).