The perimeter of a rectangle is 30meter. If the length is twice the width, what is the width?

Let the length of the rectangle be L and the width be W.

Given that the length is twice the width, Then:

L = 2W ... (1)

But we know that the perimeter is 36.

==> 2L + 2W = 36

==> 2L + L = 36

==> 3L = 36

==> L = 36/3 = 12

==> W = 12/2 = 6

Now we will calculate the area:

==> A = L * W = 12 * 6 = 72 square feet.

Then the area of the rectangle is 72 square feet.

I am 100% sure that that would be the answer!

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