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20 October, 11:31

Find the solution set of the quadratic equation over the set of complex numbers.

5x2 + 12x + 8 = 0

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Answers (2)
  1. 20 October, 12:30
    0
    Step 1: Multiply 5x2 = 10 so the equation after the first step should look like this 10 + 12x + 8 = 0.

    Step 2: Subtract 10 from the 8 and the number by itself cause whatever you do to one side you must do to the other. so the equation should look like this after the second step 12x + - 2 = 0 because we subtracted the 10 and the 8.

    Step 3: Now we must add the 2 to both sides because we have to do the inverse operation in this problem so once we've done this it should end up looking like this after the 3rd step 12x = 2 because the 2 was a negative.

    Step 4: the final step we must divide since an anytime we have a number next to a variable it means multiply but since were using order of operations we have to do the opposite/inverse operation in this problem and we would divide 12 by 2 and get our final answer as x = - 6 because the 12 would cancel itself out leaving us with 2 divided by 12 which is 0.16 or - 6 depending on if you want it simplified or not the simplified answer would be 0.16 and the non simplified version would be - 6
  2. 20 October, 14:52
    0
    Hello:

    5x²+12x+8 = 0

    delta = 12²-4 (5) (8) = - 16 = 16i² ... (i² = 1)

    delta = (4i) ²

    x1 = (-12+4i) / 2 x2 = (-12-4i) / 2

    x1 = - 6+2i x2 = - 6-2i
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