How to write y = 5/6x + 9 in standard form using integers

Standard form is

ax+by=c

a, b, c are integers and a is normally positive

get rid of all fractions

y=5/6x+9

times 6 both sides

6y=5x+54

minus 5x both sides

-5x+6y=54

times - 1 both sides

5x-6y=-54

First ... we need to get rid of fraction ... the fraction is 5/6 ... so we need to multiply both side by 6

6y = (6) (5/6) x + (6) (6)

from that ... we get

6y = 5x + 36

so according to the "Standard Form" formula ... we need to rearrange

Ax + By = C

we subtract 5x to the left

(-5x) + 6y = 36