What is the equation of the quadratic graph with a focus of (1, 1) and a directrix of y = - 1?

Hello,

The parabola has as equation y=ax²+bc+c

Δ=b²-4ac

Directrice: y = - (1+Δ) / (4a)

Focus = (-b / (2a), (1-Δ) / (4a))

1) directrice : y=-1 = - (1+b²-4ac) / (4a) = = >4a-b²+4ac=1 (1)

2) 1=-b / (2a) = = >2a=-b (2)

3) 1 = (1-b²+4ac) / (4a) = = >4a-b²+4ac=1 (3)

(1) + (2) = = >8a=2==>a=1/4

(2) = = >b=-2/4

(1) = = >4*1/4 + (-1/2) ²-4*1/4*c=1 = = >c=1/4

Parabola's Equation : y=1/4 (x²-2x+1) = (x-1) ² / 4