If f (0) = 287 and 5+4i is a root, what is the standard form of the polynomial function?

If a+bi is a root, then a-bi is also a root

5+4i is a root, 5-4i is also a root

if f (0) = 287

For f (0) = 287, therefor it is

f (x) = sometingx+287 since the x's cancel for f (0)

5-4i and 5+4i

(x - (5-4i)) and (x - (5+4i))

(x-5+4i) (x-5-4i)

x^2-10x+41

right now, f (x) = 41

41*what=287

Divide both sides by 41

what=7

time whole equation by that

f (x) = 7 (x^2-10x+41)

f (x) = 7x^2-70x+287