What are the values of x in the equation x (x-6) = 4 (x+6)

x (x-6) = x^2 - 6x 4 (x+6) = 4x + 24 First we need to eliminate the bracket by multiplying the numbers and variables from outside the bracket with the inside, we weill get : X^2 - 6x = 4x + 24 (subtract 4x and 24 from both sides) x^2 - 10x - 24 = 0 (x+2) (x-12) = 0 x+2 = 0 x-12 = 0 The value of X would be : x = - 2 x = 12